cliffton m. fischbach|A Norman window is constructed by adjoining a semicircle to ...,megatuve

Besides the gravitational force, a 3.35-kg object is subjected to one other constant force. The object starts from rest and in 1.20 s experiences a displacement of (4.15î − 3.30ĵ) m, where the direction of ĵ is the upward vertical direction. Determine the other force.

As we are evaluating from 0 to 4, x will be evaluated at 4i/n for i = 1 to n. f(x i) = (4i/n) 2 /3 - 6. ∑ 1 n 4/n ((4i/n) 2 /3 - 6) =. 4/n ((16/(3n 2)n(n+1)(2n+1)/6 - 6n) = 64/9 + 32/(3n)+ 32/(9n 2)- 24= -152/9 + 32/(3n) + 32/(9n 2). The limit as n goes to infinity is -152/9

Ariana H. asked • 01/18/21 A Norman wicliffton m. fischbachndow is constructed by adjoining a semicircle to the top of an ordinary rectangular window (see figure).

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